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20n^2+26n+8=0
a = 20; b = 26; c = +8;
Δ = b2-4ac
Δ = 262-4·20·8
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-6}{2*20}=\frac{-32}{40} =-4/5 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+6}{2*20}=\frac{-20}{40} =-1/2 $
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